Ele533 Bipolar Devices
Final Exam 1998 Question 2 Answer

The impurity profile of a pn junction is shown in figure 1. Na = 1018cm-3, a = 1023cm-4

  1. Sketch the space charge and electric field distributions.

  2. If the critical electric field for breakdown is 5x105V/cm, What is the total junction voltage(applied plus built-in) at breakdown?
Emax = qNaXp/e = q a Xn2/2e = 5x105

where the permittivity of silicon, e = 10-12

Xp = e Emax/q Na = 3.125x10-6 = 0.03125 um

Xn = sqrt[2e Emax/qa] = 7.9x10-6 = 0.079 um

Vj = V1 + V2

V1 = Emax Xp/2 = 0.78V

Integrate E from 0 to Xn to get V2

V2 = (2/3)Emax Xn = 2.64V

Vj = V1 + V2 = 3.42V